((X/5)-(4/5))^2=36

Solution for ((X/5)-(4/5))^2=36 equation:

X in (-oo:+oo)

(X/5-(4/5))^2 = 36 // - 36

(X/5-(4/5))^2-36 = 0

(X/5-4/5)^2-36 = 0

(1/5*X-4/5)^2-36 = 0

(1/5*X-4/5)^2-36 = 0

1/25*X^2-8/25*X-884/25 = 0

1/25*X^2-8/25*X-884/25 = 0

1/25*(X^2-8*X-884) = 0

X^2-8*X-884 = 0

DELTA = (-8)^2-(-884*1*4)

DELTA = 3600

DELTA > 0

X = (3600^(1/2)+8)/(1*2) or X = (8-3600^(1/2))/(1*2)

X = 34 or X = -26

1/25*(X+26)*(X-34) = 0

1/25*(X+26)*(X-34) = 0

( 1/25 )

1/25 = 0

X belongs to the empty set

( X+26 )

X+26 = 0 // - 26

X = -26

( X-34 )

X-34 = 0 // + 34

X = 34

X in { -26, 34 }